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-.5x^2+2x=-2.5
We move all terms to the left:
-.5x^2+2x-(-2.5)=0
We add all the numbers together, and all the variables
-0.5x^2+2x+2.5=0
a = -0.5; b = 2; c = +2.5;
Δ = b2-4ac
Δ = 22-4·(-0.5)·2.5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-3}{2*-0.5}=\frac{-5}{-1} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+3}{2*-0.5}=\frac{1}{-1} =-1 $
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